(3x^2-5x-8)(x+1)=0

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Solution for (3x^2-5x-8)(x+1)=0 equation: 


Simplifying
(3x2 + -5x + -8)(x + 1) = 0

Reorder the terms:
(-8 + -5x + 3x2)(x + 1) = 0

Reorder the terms:
(-8 + -5x + 3x2)(1 + x) = 0

Multiply (-8 + -5x + 3x2) * (1 + x)
(-8(1 + x) + -5x * (1 + x) + 3x2 * (1 + x)) = 0
((1 * -8 + x * -8) + -5x * (1 + x) + 3x2 * (1 + x)) = 0
((-8 + -8x) + -5x * (1 + x) + 3x2 * (1 + x)) = 0
(-8 + -8x + (1 * -5x + x * -5x) + 3x2 * (1 + x)) = 0
(-8 + -8x + (-5x + -5x2) + 3x2 * (1 + x)) = 0
(-8 + -8x + -5x + -5x2 + (1 * 3x2 + x * 3x2)) = 0
(-8 + -8x + -5x + -5x2 + (3x2 + 3x3)) = 0

Combine like terms: -8x + -5x = -13x
(-8 + -13x + -5x2 + 3x2 + 3x3) = 0

Combine like terms: -5x2 + 3x2 = -2x2
(-8 + -13x + -2x2 + 3x3) = 0

Solving
-8 + -13x + -2x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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